$\displaystyle \sum_{k=0}^nk^3=\left(\sum_{k=0}^nk \right)^2$

i did use the base case and find it true

1=1

0^3+1^3=0+1*0+1

im not good with latex but in my paper the right side just to make it more "simple" for me i did write it as 2 times that instend to have ^2...

ima proof for k+1 and need tips :S im lost