So it wants me to find a formula. I got ((-9)(x-1))/((x+3)(x-3)). The last part of the graph is not coming out correctly though. How do I alter the formula so that the right side of the graph flips over the x-axis?
So it wants me to find a formula. I got ((-9)(x-1))/((x+3)(x-3)). The last part of the graph is not coming out correctly though. How do I alter the formula so that the right side of the graph flips over the x-axis?
Hello, DasRabbit!
There are vertical asymptotes at and
has in the denominator.
With the "usual" vertical asymptote, the graph goes to on one side
. . and to on the other side (as it does at ).
At , the graph goes to on both sides.
This indicates that the factor in the denominator is to an even power.
. . Hence, the denominator has: .
Since there is a horizontal asymptote , the numerator has a degree less than 3.
. . Assume (for simplicity) that the numerator is linear.
We have: .
We want:
We want:
Therefore: .
Test a few points to ensure that graph is on the correct sides of the x-axis.