http://i46.tinypic.com/vrdoo5.png

So it wants me to find a formula. I got ((-9)(x-1))/((x+3)(x-3)). The last part of the graph is not coming out correctly though. How do I alter the formula so that the right side of the graph flips over the x-axis?

Printable View

- Nov 5th 2012, 07:56 PMDasRabbitFinding a polynomial equation based off its graph
http://i46.tinypic.com/vrdoo5.png

So it wants me to find a formula. I got ((-9)(x-1))/((x+3)(x-3)). The last part of the graph is not coming out correctly though. How do I alter the formula so that the right side of the graph flips over the x-axis? - Nov 5th 2012, 08:54 PMSorobanRe: Finding a polynomial equation based off its graph
Hello, DasRabbit!

There are vertical asymptotes at and

has in the denominator.

With the "usual" vertical asymptote, the graph goes to on one side

. . and to on the other side (as it does at ).

At , the graph goes to onsides.*both*

This indicates that the factor in the denominator is to anpower.*even*

. . Hence, the denominator has: .

Since there is a horizontal asymptote , the numerator has a degree less than 3.

. . Assume (for simplicity) that the numerator is linear.

We have: .

We want:

We want:

Therefore: .

Test a few points to ensure that graph is on the correct sides of the*x*-axis.