Re: Inverse function Help

Re: Inverse function Help

Skeeter "completed the square". You could also solve for y using the quadratic formula- which, of course, comes from "completing the square".

Re: Inverse function Help

When talking about a function, domain and range are necessary to be mentioned, a mere calculation without a domain does not qualify for a function. The original function is defined on [5/6, infinity) --> [-37/12, infinity), and the inverse is defined from [-37/12, infinity) --> [5/6, infinity). Making the function bijective like this is necessary for an inverse being defined.

Salahuddin

Maths online