Hello again people. I need a tad of help with my homework. Here are the questions I am having trouble with.

$\displaystyle f(x) = \frac {7x - m}{2 - nx}$

So, I need to find the values of m and n such that the vertical asymptote is x = 6 and the x intercept is 5. Im guessing for the value to be an assymptote, we have to look at just the bottom and that has to = to 0. So I get

2 - n(6) = 0

-2 = -n(6)

-2/6 = -n = -1/3

or

n = 1/3

but im not sure if thats right.

Ok now the other question.

Find the value if p for which f(x) would have a removable discontinuity and then define f(p) so that $\displaystyle f(x) = \frac {x^2 - 6x +9}{x-p}$

I have no clue where I am even supposed to start with this question. Someone explain this to me because wouldn't there always be a value that would give you 0 on the bottom?

Thanks

Chris