Hello again people. I need a tad of help with my homework. Here are the questions I am having trouble with.
So, I need to find the values of m and n such that the vertical asymptote is x = 6 and the x intercept is 5. Im guessing for the value to be an assymptote, we have to look at just the bottom and that has to = to 0. So I get
2 - n(6) = 0
-2 = -n(6)
-2/6 = -n = -1/3
n = 1/3
but im not sure if thats right.
Ok now the other question.
Find the value if p for which f(x) would have a removable discontinuity and then define f(p) so that
I have no clue where I am even supposed to start with this question. Someone explain this to me because wouldn't there always be a value that would give you 0 on the bottom?
ok so umm for the first question because its an x intercept, the y value has to = 0 so i get 7(5) - n which gives me n as -35. So the value of n is -35 and m is 1/3?
and for the 2nd question
so we can factor out and x-3 which means the value of p is 3
how would i find a value which would make the functions continuous for all values?