Periods and phase shift?

**M670** · October 18th 2012, 03:21 PM

Let

.
What is the amplitude?
What is the period?
What is the phase shift?

I put 3pi as my period because I believe it would be 2pi/6pi which is 3 pi?
and the phase shift I thought it was 6e_⁴, but thats wrong and I don't know why ?

**skeeter** · October 18th 2012, 03:43 PM

$y = A\sin(Bx + C) + D$

$|A|$ = amplitude

$\frac{2\pi}{|B|}$ = period

$\frac{C}{B}$ = phase shift

$D$ = vertical shift

btw, work on your division skills ...

$\frac{2\pi}{6\pi} = \frac{1}{3}$

**M670** · October 18th 2012, 05:12 PM

Originally Posted by skeeter

$y = A\sin(Bx + C) + D$

$|A|$ = amplitude

$\frac{2\pi}{|B|}$ = period

$\frac{C}{B}$ = phase shift

$D$ = vertical shift

btw, work on your division skills ...

$\frac{2\pi}{6\pi} = \frac{1}{3}$

Yes my division was off, but I am unable to get the phase shift would it not be 6e^4 over 6pi ?

**skeeter** · October 18th 2012, 05:17 PM

Originally Posted by M670

Yes my division was off, but I am unable to get the phase shift would it not be 6e^4 over 6pi ?

$\frac{e^4}{\pi}$

**M670** · October 18th 2012, 06:02 PM

i came to that conclusion earlier but It came back as being wrong?

**skeeter** · October 19th 2012, 03:10 AM

Originally Posted by M670

i came to that conclusion earlier but It came back as being wrong?

were you also required a direction for the phase shift?

**M670** · October 19th 2012, 10:50 AM

I was not required to give a direction just the value of the phase shift

**skeeter** · October 19th 2012, 01:49 PM

try $-\frac{e^4}{\pi}$ ... see what happens

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