1. Periods and phase shift?

Let .
What is the amplitude?
What is the period?
What is the phase shift?

I put 3pi as my period because I believe it would be 2pi/6pi which is 3 pi?
and the phase shift I thought it was 6e4, but thats wrong and I don't know why ?

2. Re: Periods and phase shift?

$\displaystyle y = A\sin(Bx + C) + D$

$\displaystyle |A|$ = amplitude

$\displaystyle \frac{2\pi}{|B|}$ = period

$\displaystyle \frac{C}{B}$ = phase shift

$\displaystyle D$ = vertical shift

btw, work on your division skills ...

$\displaystyle \frac{2\pi}{6\pi} = \frac{1}{3}$

3. Re: Periods and phase shift?

Originally Posted by skeeter
$\displaystyle y = A\sin(Bx + C) + D$

$\displaystyle |A|$ = amplitude

$\displaystyle \frac{2\pi}{|B|}$ = period

$\displaystyle \frac{C}{B}$ = phase shift

$\displaystyle D$ = vertical shift

btw, work on your division skills ...

$\displaystyle \frac{2\pi}{6\pi} = \frac{1}{3}$
Yes my division was off, but I am unable to get the phase shift would it not be 6e^4 over 6pi ?

4. Re: Periods and phase shift?

Originally Posted by M670
Yes my division was off, but I am unable to get the phase shift would it not be 6e^4 over 6pi ?
$\displaystyle \frac{e^4}{\pi}$

5. Re: Periods and phase shift?

i came to that conclusion earlier but It came back as being wrong?

6. Re: Periods and phase shift?

Originally Posted by M670
i came to that conclusion earlier but It came back as being wrong?
were you also required a direction for the phase shift?

7. Re: Periods and phase shift?

I was not required to give a direction just the value of the phase shift

8. Re: Periods and phase shift?

try $\displaystyle -\frac{e^4}{\pi}$ ... see what happens