Re: Periods and phase shift?

$\displaystyle y = A\sin(Bx + C) + D$

$\displaystyle |A|$ = amplitude

$\displaystyle \frac{2\pi}{|B|}$ = period

$\displaystyle \frac{C}{B}$ = phase shift

$\displaystyle D$ = vertical shift

btw, work on your division skills ...

$\displaystyle \frac{2\pi}{6\pi} = \frac{1}{3}$

Re: Periods and phase shift?

Quote:

Originally Posted by

**skeeter** $\displaystyle y = A\sin(Bx + C) + D$

$\displaystyle |A|$ = amplitude

$\displaystyle \frac{2\pi}{|B|}$ = period

$\displaystyle \frac{C}{B}$ = phase shift

$\displaystyle D$ = vertical shift

btw, work on your division skills ...

$\displaystyle \frac{2\pi}{6\pi} = \frac{1}{3}$

Yes my division was off, but I am unable to get the phase shift would it not be 6e^4 over 6pi ?

Re: Periods and phase shift?

Quote:

Originally Posted by

**M670** Yes my division was off, but I am unable to get the phase shift would it not be 6e^4 over 6pi ?

$\displaystyle \frac{e^4}{\pi}$

Re: Periods and phase shift?

i came to that conclusion earlier but It came back as being wrong?

Re: Periods and phase shift?

Quote:

Originally Posted by

**M670** i came to that conclusion earlier but It came back as being wrong?

were you also required a direction for the phase shift?

Re: Periods and phase shift?

I was not required to give a direction just the value of the phase shift

Re: Periods and phase shift?

try $\displaystyle -\frac{e^4}{\pi}$ ... see what happens