Thread: This equation has two roots

3x^(6)e^(-2x)-9x^(7)e^(-2x)=0 has two roots

Where do I even start?

I would start by dividing through by any non-zero numbers that are common to both sides of the equation. (I presume you know that is not 0 for ny x.)

Originally Posted by RD33

3x^(6)e^(-2x)-9x^(7)e^(-2x)=0 has two roots
Where do I even start?

Factor it:

Ok I got the answer 0 and 1/3 but how did you factor it. Where does the (1-3x) come from?

Originally Posted by RD33

Ok I got the answer 0 and 1/3 but how did you factor it. Where does the (1-3x) come from?

Can you factor What do you get?