3x^(6)e^(-2x)-9x^(7)e^(-2x)=0 has two roots

Where do I even start?

Printable View

- Oct 15th 2012, 07:55 AMRD33This equation has two roots
3x^(6)e^(-2x)-9x^(7)e^(-2x)=0 has two roots

Where do I even start? - Oct 15th 2012, 08:03 AMHallsofIvyRe: This equation has two roots
I would start by dividing through by any non-zero numbers that are common to both sides of the equation. (I presume you know that $\displaystyle e^x$ is not 0 for ny x.)

- Oct 15th 2012, 08:13 AMPlatoRe: This equation has two roots
- Oct 15th 2012, 09:24 AMRD33Re: This equation has two roots
Ok I got the answer 0 and 1/3 but how did you factor it. Where does the (1-3x) come from?

- Oct 15th 2012, 09:59 AMPlatoRe: This equation has two roots