Solve for x: (9/4)log4x=10 this is what I got: log4 (x^(9/4))=10 4^10 = x^(9/4) (4^10)^(4/9) = (x^(9/4))^(4/9) 4^(4/10) = x 4^(2/5) =x am I on the right track?
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Originally Posted by RD33 Solve for x: (9/4)log4x=10 this is what I got: log4 (x^(9/4))=10 4^10 = x^(9/4) (4^10)^(4/9) = (x^(9/4))^(4/9) 4^(4/10) = x 4^(2/5) =x am I on the right track? First of all I presume this is log base 4? I'd recommend that you start this way: Can you work out the rest? -Dan
I think so. I would have to put it into exponential from right? So I would end up with 4^(40/9) = x ?
Hello, RD33! This is what I got: . . . . . . . . . . Am I on the right track? Your reasoning is excellent. Just one error in arithmetic. I solved it like this: . . . . . . . . . . .
Ok thank you
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