Hint:note that if we factored this, it would be the difference of two squares, with f being one factor

we want[b] [f+g][x]=3(x^2)

simply solve for

[c] [f/g][x]=1Hint:any number divided by itself is 1

we want[d] f[g[x]]=9(x^4)+1

solve for

i can't really think of a nice hint to give you here...[e] g[f[x]]=9(x^4)+1