Getting to the root of the equation

The equation http://webwork.mathstat.concordia.ca...dc237159c1.png has two roots. Find the smaller and larger one?

so I came up with 2x²e^-5x(3-3x)=0

Just not sure where to go from here?

Quote:

---

Originally Posted by M670

The equation http://webwork.mathstat.concordia.ca...dc237159c1.png has two roots. Find the smaller and larger one?

so I came up with 2x²e^-5x(3-3x)=0

Just not sure where to go from here?

---

You need to use the zero product principle. This would give



Only two of these equations have solutions.