How do I solve this Exponential and Logarithmic Function?

1.Find the value of http://www.mathway.com/math_image.as...MB03?p=30?p=22 when http://www.mathway.com/math_image.as...MB03?p=34?p=22 = 4.

My attempt: http://www.mathway.com/math_image.as...MB03?p=30?p=22=http://www.mathway.com/math_image.as...MB03?p=34?p=22= 4

http://www.mathway.com/math_image.as...MB03?p=58?p=22=4

27x=1

x= 1/27.

When checked on a calculator it doesn't work. I don't understand what to do. Is there a way to solve this without using calculators?

2. Solve the equation http://www.mathway.com/math_image.as...013?p=138?p=22

I don't have an attempt since I can't understand what operation to use.

Whoops, wrong category. Can I request for a Moderator (if there is one in here) to relocate this to Algebra?

Now how do I mark this thread as [SOLVED]? There was a prefix box when I was just making this thread earlier.

Re: How do I solve this Exponential and Logarithmic Function?(Sorry, wrong category)

Quote:

Originally Posted by

**RPSGCC733**

Re: How do I solve this Exponential and Logarithmic Function?(Sorry, wrong category)

Quote:

Originally Posted by

**RPSGCC733**

Is the second question trying to solve for when ?

Re: How do I solve this Exponential and Logarithmic Function?

Note that

where thus you have to solve

Re: How do I solve this Exponential and Logarithmic Function?(Sorry, wrong category)

Quote:

Originally Posted by

**Prove It**

Ah. Thanks! Didn't think that 3^{9x} was 3^3 raised to the third power all along.

Yeah, it was trying to solve for x.

Re: How do I solve this Exponential and Logarithmic Function?

1.) A similar approach to the one already posted:

Re: How do I solve this Exponential and Logarithmic Function?

Quote:

Originally Posted by

**Siron** Note that

where

thus you have to solve

Many thanks.

Isn't multiplication in Logarithm denoted with a + sign? That part confused me.

Nevermind, I just realized it wasn't multiplication. was a logarithm of

Re: Exponential and Logarithmic Function?(Sorry, wrong category)

Hello, RPSGCC733!