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Math Help - Just need a little help to figure out x in this log question

  1. #1
    Member M670's Avatar
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    Just need a little help to figure out x in this log question

    Find the largest value of that satisfies:
    I have rewritten it like this log2(x^2/(x+1))=4 which in exponent form is 2^4=(x^2/(x+1)) so 16=(x^2/(x+1))
    but I am still rusty need some direction
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    Re: Just need a little help to figure out x in this log question

    Quote Originally Posted by M670 View Post
    Find the largest value of that satisfies:
    I have rewritten it like this log2(x^2/(x+1))=4 which in exponent form is 2^4=(x^2/(x+1)) so 16=(x^2/(x+1))
    Keep going: x^2-16x-16=0
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    Member M670's Avatar
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    Re: Just need a little help to figure out x in this log question

    Quote Originally Posted by Plato View Post
    Keep going: x^2-16x-16=0
    Ok form here I am sure I can do it, but can elaborate which rules you applied to get to that point
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    Re: Just need a little help to figure out x in this log question

    \frac{x^2}{x+1} = 16

    multiply both sides by (x+1) ...

    x^2 = 16(x+1)

    distribute the right side and collect all terms on the left side to set the quadratic equation = 0

    remember when you finish finding solutions for x, x+1 > 0
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