Find the largest value of that satisfies: I have rewritten it like this log_{2}(x^2/(x+1))=4 which in exponent form is 2^4=(x^2/(x+1)) so 16=(x^2/(x+1))
but I am still rusty need some direction
Find the largest value of that satisfies: I have rewritten it like this log_{2}(x^2/(x+1))=4 which in exponent form is 2^4=(x^2/(x+1)) so 16=(x^2/(x+1))
but I am still rusty need some direction
$\displaystyle \frac{x^2}{x+1} = 16$
multiply both sides by $\displaystyle (x+1)$ ...
$\displaystyle x^2 = 16(x+1)$
distribute the right side and collect all terms on the left side to set the quadratic equation = 0
remember when you finish finding solutions for $\displaystyle x$, $\displaystyle x+1 > 0$