Find the largest value of http://webwork.mathstat.concordia.ca...dd0b8b8e91.png that satisfies: I have rewritten it like this log_{2}(x^2/(x+1))=4 which in exponent form is 2^4=(x^2/(x+1)) so 16=(x^2/(x+1))

but I am still rusty need some direction

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- Oct 13th 2012, 12:44 PMM670Just need a little help to figure out x in this log question
Find the largest value of http://webwork.mathstat.concordia.ca...dd0b8b8e91.png that satisfies: I have rewritten it like this log

_{2}(x^2/(x+1))=4 which in exponent form is 2^4=(x^2/(x+1)) so 16=(x^2/(x+1))

but I am still rusty need some direction - Oct 13th 2012, 12:53 PMPlatoRe: Just need a little help to figure out x in this log question
- Oct 13th 2012, 01:06 PMM670Re: Just need a little help to figure out x in this log question
- Oct 13th 2012, 01:29 PMskeeterRe: Just need a little help to figure out x in this log question
$\displaystyle \frac{x^2}{x+1} = 16$

multiply both sides by $\displaystyle (x+1)$ ...

$\displaystyle x^2 = 16(x+1)$

distribute the right side and collect all terms on the left side to set the quadratic equation = 0

remember when you finish finding solutions for $\displaystyle x$, $\displaystyle x+1 > 0$