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Math Help - Logarithms

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    Logarithms

    Why is it that if you have this equation (log6+logx)logx = 3, the result would become (logx)^2+(log6)logx-3=0 I don't understand why the logx squares.
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    MHF Contributor MarkFL's Avatar
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    Re: Logarithms

    When you distribute the \log(x) to the two terms within the parentheses, one of the resulting terms is \log^2(x).

    For example, if you have (x+y)y distributing the y gives xy+y^2.
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    Re: Logarithms

    Quote Originally Posted by Eraser147 View Post
    Why is it that if you have this equation (log6+logx)logx = 3, the result would become (logx)^2+(log6)logx-3=0 I don't understand why the logx squares.
    Do you understand that (b+a)a=3 implies a^2+ba-3=0~?

    If you do, then that explains it.
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