# Math Help - Logarithms

1. ## Logarithms

Why is it that if you have this equation $(log6+logx)logx = 3$, the result would become $(logx)^2+(log6)logx-3=0$ I don't understand why the logx squares.

2. ## Re: Logarithms

When you distribute the $\log(x)$ to the two terms within the parentheses, one of the resulting terms is $\log^2(x)$.

For example, if you have $(x+y)y$ distributing the $y$ gives $xy+y^2$.

3. ## Re: Logarithms

Originally Posted by Eraser147
Why is it that if you have this equation $(log6+logx)logx = 3$, the result would become $(logx)^2+(log6)logx-3=0$ I don't understand why the logx squares.
Do you understand that $(b+a)a=3$ implies $a^2+ba-3=0~?$

If you do, then that explains it.