# Logarithms

• October 12th 2012, 09:40 AM
Eraser147
Logarithms
Why is it that if you have this equation $(log6+logx)logx = 3$, the result would become $(logx)^2+(log6)logx-3=0$ I don't understand why the logx squares.
• October 12th 2012, 09:52 AM
MarkFL
Re: Logarithms
When you distribute the $\log(x)$ to the two terms within the parentheses, one of the resulting terms is $\log^2(x)$.

For example, if you have $(x+y)y$ distributing the $y$ gives $xy+y^2$.
• October 12th 2012, 09:57 AM
Plato
Re: Logarithms
Quote:

Originally Posted by Eraser147
Why is it that if you have this equation $(log6+logx)logx = 3$, the result would become $(logx)^2+(log6)logx-3=0$ I don't understand why the logx squares.

Do you understand that $(b+a)a=3$ implies $a^2+ba-3=0~?$

If you do, then that explains it.