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Math Help - More logs( exponent to log)

  1. #1
    Member M670's Avatar
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    More logs( exponent to log)

    Solve for :

    So if I transform this into log form
    I should have Log(4^4x-8)=log(3^7x-2)
    (4x-8)log(4)=(7x-2)log(3)
    4log(4)x-8log(4)=7log(3)x-2log(3)
    4log(4)x-7log(3)x=8log(4)-2log(3)
    then solve for x= 8log(4)-2log(3) /4log(4)-7log(3) = -4.16?
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: More logs( exponent to log)

    Your algebra looks good, my calculator gives x\approx-4.14577164546
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