Solve for http://webwork.mathstat.concordia.ca...dd0b8b8e91.png:http://webwork.mathstat.concordia.ca...2d46848bf1.png

So if I transform this into log form

I should have Log(4^4x-8)=log(3^7x-2)

(4x-8)log(4)=(7x-2)log(3)

4log(4)x-8log(4)=7log(3)x-2log(3)

4log(4)x-7log(3)x=8log(4)-2log(3)

then solve for x= 8log(4)-2log(3) /4log(4)-7log(3) = -4.16?