12^{3x-1}= 598^{2x-3}

I need to simplify the equation first and then plug it into a calculator to solve for x. The problem is, I don't know how to simplify this type of equation with two exponents..help (Headbang)

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- Oct 9th 2012, 05:04 PMchopper07Solve the log function using graphing calculator
12

^{3x-1}= 598^{2x-3}

I need to simplify the equation first and then plug it into a calculator to solve for x. The problem is, I don't know how to simplify this type of equation with two exponents..help (Headbang) - Oct 9th 2012, 05:07 PMchopper07Re: Solve the log function using graphing calculator
Oh, and how do I put in the numbers on a graphing calc if I want to find for example 3log2 ?

- Oct 9th 2012, 05:22 PMskeeterRe: Solve the log function using graphing calculator
$\displaystyle \log(12^{3x-1}) = \log(598^{2x-3})$

$\displaystyle (3x-1)\log{12} = (2x-3)\log{598}$

now graph ...

$\displaystyle y = (3x-1)\log{12} - (2x-3)\log{598}$

... and look for the zero. - Oct 9th 2012, 05:28 PMchopper07Re: Solve the log function using graphing calculator
But the equation y=(3x-1)log12-(2x-3)log598 is not simplified ! It has to be simplified until it is in terms of x. how do i do that?

- Oct 9th 2012, 05:38 PMskeeterRe: Solve the log function using graphing calculator
the equation is in terms of x ... do you mean solve for x ?

- Oct 9th 2012, 05:51 PMchopper07Re: Solve the log function using graphing calculator
yes, that's what i mean. I mean I have to make the simplified equation look like x=something so that I can easily put it into the calculator. in our class we were told not to graph them on the graphing calc

- Oct 9th 2012, 05:52 PMchopper07Re: Solve the log function using graphing calculator
I'm not sure, but I think your equation was in terms of y instead.

- Oct 10th 2012, 03:08 AMskeeterRe: Solve the log function using graphing calculator
$\displaystyle (3x-1)\log{12} = (2x-3)\log{598}$

this is a linear equation ... you try solving for x. remember that $\displaystyle \log{12}$ and $\displaystyle \log{598}$ are just constants.