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Math Help - Solving Log Function

  1. #1
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    Solving Log Function

    Okay, so I have to find x in the log equation. Please don't just tell me the answer, I need an explanation and what I'm doing wrong.

    log4(x+2)-log4(x-3)=2




    I've tried dividing (x+2) and (x+3) since they have the same base, and then setting it equal to 2. But I can never get the right answer!!!!
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  2. #2
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    Re: Solving Log Function

    \log_4(x+2) - \log_4(x-3) = 2

    \log_4\left(\frac{x+2}{x-3}\right) = 2

    change to an exponential equation ...

    \frac{x+2}{x-3} = 4^2

    finish it
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  3. #3
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    Re: Solving Log Function

    oh, i get it now. thank you
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