
Solving Log Function
Okay, so I have to find x in the log equation. Please don't just tell me the answer, I need an explanation and what I'm doing wrong. (Worried)
log_{4}(x+2)log_{4}(x3)=2
I've tried dividing (x+2) and (x+3) since they have the same base, and then setting it equal to 2. But I can never get the right answer!!!!

Re: Solving Log Function
$\displaystyle \log_4(x+2)  \log_4(x3) = 2$
$\displaystyle \log_4\left(\frac{x+2}{x3}\right) = 2$
change to an exponential equation ...
$\displaystyle \frac{x+2}{x3} = 4^2$
finish it

Re: Solving Log Function
oh, i get it now. thank you