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Originally Posted by Eraser147 Click the image to enlarge please. BUT that can be greatly simplified.
Yes, but going from there, I don't know how to find the x. It's just too confusing from there. I don't know which exponent I can factor out.
Plato is correct. If you want f of g, you just plug the g function into the x spot on the f function. then Does this make sense? If I am incorrect on this please correct me!
Originally Posted by Eraser147 Yes, but going from there, I don't know how to find the x. It's just too confusing from there. I don't know which exponent I can factor out. Well I did say "that can be greatly simplified."
Hello, Eraser147! . . . . . . . . . . . . . . . . . .
^ Thankyou that made more sense. I had to separate the 7s.
Just one more question, can someone explain why when 7 is extended to the power of log 7 and raised to the x^5, why does it cancel and equate to x^5?
Originally Posted by Eraser147 Just one more question, can someone explain why when 7 is extended to the power of log 7 and raised to the x^5, why does it cancel and equate to x^5?
Thanks
That is, pretty much, the definition of " "- it is the inverse function to : .
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