# Math Help - Logarithms

1. ## Logarithms

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2. ## Re: Logarithms

What do you think is the best first step?

3. ## Re: Logarithms

Hey Eraser147.

Try collecting the 10^(t) terms to one side and then use the relationship that log_10(10^t) = t where log_10(x) = log(x)/log(10) where log(x) is the natural logarithm.

4. ## Re: Logarithms

I ended up with $10^t+1=.8*10^t+1.6$. I don't know where to go from there.

5. ## Re: Logarithms

10^(t) - 0.8*10^(t) = 1.6 - 1 which means
0.2*10^(t) = 0.6 which means
10^(t) = 0.6/0.2 = 3.

6. ## Re: Logarithms

Oh... THANKS A BUNCH. My error was not realizing I should subtract the 0.8*10^(t)

7. ## Re: Logarithms

Originally Posted by Eraser147
I find this whole thread off.

$10^t+7.9=1.1(10^t)+7.7$

$0.1(10^t)=0.2$

$10^t=2$

$t=\log_{10}(2)$