Rewrite Log Function in terms of A and B?

This has been driving me up the wall, I have a test the day after tomorrow and this is DEFINITELY going to be on the test. It seems simple, but for some reason I can't get the hang of it, please help. (Crying)

***Rewrite the equation in terms of A and B

A=Log_{3}4 , B=log_{3}5

this equation--> log_{3}(15/2)

I've tried 3b+(a/2), but thats wrong. I know why it's wrong, but I dont know how to get the right answer.

Re: Rewrite Log Function in terms of A and B?

Quote:

Originally Posted by

**chopper07** This has been driving me up the wall, I have a test the day after tomorrow and this is DEFINITELY going to be on the test. It seems simple, but for some reason I can't get the hang of it, please help. (Crying)

***Rewrite the equation in terms of A and B

A=Log_{3}4 , B=log_{3}5

this equation--> log_{3}(15/2)

I've tried 3b+(a/2), but thats wrong. I know why it's wrong, but I dont know how to get the right answer.

Hint:

Re: Rewrite Log Function in terms of A and B?

, so .

You have values for and . The only thing left is . Recall that if then . Here a = 3 and b = 3, so what's the value of c? Hence what's the value of ? Post back with your solution and we'll check it for you.

Re: Rewrite Log Function in terms of A and B?

Ohh, ok i get it now. thank you !! (Hi)

Re: Rewrite Log Function in terms of A and B?

Wait, so would it be 1+B+(a/2) ?