A straight line is given as 2(x+4) = -2(y-5) = -3(z-6),
(a)determine the vector equation of the straight line. The answer I found is r = -4i +5j +6k + t(3i -3j +2k), is this correct?
(b)find the coordinate of a point Q that lies at the straight line such the |(OQ) ⃗ |= 3. I can't get this one, someone please guide me, thanks.