Thread: Finding f^-1(x)

Let . Find .

make its y=15x^3-3
y+3=15x^3

I think up to this point I am right,

My final answer is this y= but its wrong

Originally Posted by M670

Let . Find .

make its y=15x^3-3
y+3=15x^3

I think up to this point I am right,

My final answer is this y= but its wrong

When finding an inverse function, the x and y values swap. So if is given by then will be defined by



So the inverse function is

I just tired that answer and the program is still telling me I am wrong??

You must be entering it wrong then. Try ((x + 3)/(15))^(1/3).

thank you I entered it like 3sqrt((x+3)/15) which I guess was telling it 3 times the sqrt

Originally Posted by M670

thank you I entered it like 3sqrt((x+3)/15) which I guess was telling it 3 times the sqrt

cube root, not square root.