Let . Find . make its y=15x^3-3 y+3=15x^3 I think up to this point I am right, My final answer is this y= but its wrong
Follow Math Help Forum on Facebook and Google+
Originally Posted by M670 Let . Find . make its y=15x^3-3 y+3=15x^3 I think up to this point I am right, My final answer is this y= but its wrong When finding an inverse function, the x and y values swap. So if is given by then will be defined by So the inverse function is
I just tired that answer and the program is still telling me I am wrong??
You must be entering it wrong then. Try ((x + 3)/(15))^(1/3).
thank you I entered it like 3sqrt((x+3)/15) which I guess was telling it 3 times the sqrt
Originally Posted by M670 thank you I entered it like 3sqrt((x+3)/15) which I guess was telling it 3 times the sqrt cube root, not square root.
View Tag Cloud