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Math Help - Quadratic Functions

  1. #1
    TH1
    TH1 is offline
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    Quadratic Functions

    Find the zeros,equation of axis of symmetry and the coordinates of the vertex
    I wasnt sure what to do for this one since it was the other way around

    g(x)=(x-10)(2-x)
    g(x)=(5-x)(5+x)

    Determine the maximum or minimum Value
    g(x)=(7-x)(x+2)
    g(x)=(2x+3)(8-x)
    x^2+7x+10
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  2. #2
    MHF Contributor
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    Quote Originally Posted by TH1 View Post
    Find the zeros,equation of axis of symmetry and the coordinates of the vertex
    I wasnt sure what to do for this one since it was the other way around

    g(x)=(x-10)(2-x)
    g(x)=(5-x)(5+x)

    Determine the maximum or minimum Value
    g(x)=(7-x)(x+2)
    g(x)=(2x+3)(8-x)
    x^2+7x+10
    The other way around?

    g(x) = (x -10)(2 -x)
    g(x) = 2x -x^2 -20 +10x
    g(x) = -x^2 +12x -20
    It should be the same direction now.

    The zeros are of course x = 10 and x = 2.

    Axis of symmetry:
    g(x) = -x^2 +12x -20
    At vertex, x = -b/2a
    x = -12/(2(-1)) = 6
    So, the axis of symmetry is x = 6

    The coordinates of the vertex:
    g(6) = -(6^2) +12(6) -20 = 16
    So, (6,16) ------the vertex.

    -----------------------------------------

    The rest should be the same in rearranging them from "the other around".
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