Thread: Quadratic Functions

Find the zeros,equation of axis of symmetry and the coordinates of the vertex
I wasnt sure what to do for this one since it was the other way around

g(x)=(x-10)(2-x)
g(x)=(5-x)(5+x)

Determine the maximum or minimum Value
g(x)=(7-x)(x+2)
g(x)=(2x+3)(8-x)
x^2+7x+10

Originally Posted by TH1

Find the zeros,equation of axis of symmetry and the coordinates of the vertex
I wasnt sure what to do for this one since it was the other way around

g(x)=(x-10)(2-x)
g(x)=(5-x)(5+x)

Determine the maximum or minimum Value
g(x)=(7-x)(x+2)
g(x)=(2x+3)(8-x)
x^2+7x+10

The other way around?

g(x) = (x -10)(2 -x)
g(x) = 2x -x^2 -20 +10x
g(x) = -x^2 +12x -20
It should be the same direction now.

The zeros are of course x = 10 and x = 2.

Axis of symmetry:
g(x) = -x^2 +12x -20
At vertex, x = -b/2a
x = -12/(2(-1)) = 6
So, the axis of symmetry is x = 6

The coordinates of the vertex:
g(6) = -(6^2) +12(6) -20 = 16
So, (6,16) ------the vertex.

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The rest should be the same in rearranging them from "the other around".