Find a formula for the quadratic function whose graph has the given properties: A y-intercept of y = 7 and x-intercepts at x = 1, 4 Help please! i don't know how to find the formula...
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Write down an arbitrary quadratic function: For Example: y = a(x-b)(x-c) Fill in the details: "x-intercepts at x = 1, 4" y = a(x-1)(x-4) You do the y-intercept.
it wouldn't be y = (1-b)(4-c) because they're x's?
Originally Posted by sksksk it wouldn't be y = (1-b)(4-c) because they're x's? TKHunny is telling you the general form of a quadratic function: $\displaystyle y = a(x - b)(x - c)$ where b and c are the two zeros of the quadratic. You are applying this to your specific problem where b = 1 and c = 4. -Dan
ohh... got it. thanks
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