Find a formula for the quadratic function whose graph has the given properties:
A y-intercept of y = 7 and x-intercepts at x = 1, 4
Help please! i don't know how to find the formula...
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Write down an arbitrary quadratic function:
y = a(x-b)(x-c)
Fill in the details:
"x-intercepts at x = 1, 4"
y = a(x-1)(x-4)
You do the y-intercept.
it wouldn't be y = (1-b)(4-c) because they're x's?
Originally Posted by sksksk it wouldn't be y = (1-b)(4-c) because they're x's? TKHunny is telling you the general form of a quadratic function:
where b and c are the two zeros of the quadratic.
You are applying this to your specific problem where b = 1 and c = 4.
ohh... got it. thanks
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