Printable View
2 more problems:
Attachment 24924
I insert the above in brackets into the combination formula nCk
which becomes:
solving for n I get 1.12 or 3.33, book gives the answer of 4.
I am incorrect for the second question(45) as well using the same method, my answer is 0/1/-7/-8/-9(approximated), book answer is 7.
Can you show how you get your answers? The first problem reduces to a quadratic equation. The second problem reduces to an equation of fourth degree, but after cancellation it also becomes a quadratic equation.
I put both sides of the equations into a graphing calculator and use the intersections as "n".Quote:
Originally Posted by emakarov
(n!)/((n-2)!(n-(n-2))!)=6 - Wolfram|Alpha
Looking back on my cellphones wolfram application history it was a transcription error after all.(for 43)
45:
((n+2)!/(4!(&# 40;n-2)!))=6((n!)&# 41;/(2!(n-2)!) - Wolfram|Alpha
apologies
Quote:
Originally Posted by Greymalkin2 more problems:
Attachment 24924
I insert the above in brackets into the combination formula nCk
which becomes:
and
Put those equal we get
