# Thread: Finding domain and Range

1. ## Finding domain and Range

I don't know for some reason this question is confusing me and I can't find an example similar in my text book
domain and range of :

2. ## Re: Finding domain and Range

Originally Posted by M670
I don't know for some reason this question is confusing me and I can't find an example similar in my text book
domain and range of :
The range is $(-6,\infty)$. What is the domain?

3. ## Re: Finding domain and Range

You should be familiar w/ the graph of the parent function $y = \frac{1}{x^2}$. Its domain is the same as for f(x).

... what transformation has occurred to the parent function by subtracting 6 ? How does this affect the range?

4. ## Re: Finding domain and Range

The domain should be all real number except where the denominator is zero

5. ## Re: Finding domain and Range

Originally Posted by M670
The domain should be all real number except where the denominator is zero
Correct!

6. ## Re: Finding domain and Range

Originally Posted by skeeter
You should be familiar w/ the graph of the parent function $y = \frac{1}{x^2}$. Its domain is the same as for f(x).

... what transformation has occurred to the parent function by subtracting 6 ? How does this affect the range?
I believe by subtracting 6 we are getting a negative y value

7. ## Re: Finding domain and Range

To represent the domain in interval notation it would be (-infinity,0) U (0, infinity)

8. ## Re: Finding domain and Range

Originally Posted by Plato
The range is $(-6,\infty)$. What is the domain?
Could you give me the steps you used to find the range
I know its the max point on the Y axis where x can effect it, so this would mean that my graph would not go past -6on the y

9. ## Re: Finding domain and Range

Originally Posted by M670
Could you give me the steps you used to find the range
I know its the max point on the Y axis where x can effect it, so this would mean that my graph would not go past -6on the y
The range of $\frac{1}{x^2}$ is $(0,\infty)$.

The range of $\frac{1}{x^2}-6$ is $(-6,\infty)$.

10. ## Re: Finding domain and Range

ahh I see said the blind man