http://webwork.mathstat.concordia.ca...3ee9b0cf31.png

I am trying to figure out how to write the domain in interval notation

i reduced the denominator to (x-4)^2 but am stuck now

any help would be great

Thanks

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- Sep 23rd 2012, 06:48 AMM670Domain of a function
http://webwork.mathstat.concordia.ca...3ee9b0cf31.png

I am trying to figure out how to write the domain in interval notation

i reduced the denominator to (x-4)^2 but am stuck now

any help would be great

Thanks - Sep 23rd 2012, 06:57 AMSironRe: Domain of a function
What you have said is not entirely correct, you can reduce the denominator to $\displaystyle (x+4)^2$ thus

$\displaystyle f(x) = \frac{x-2}{x^2+8x+16} = \frac{x-2}{(x+4)^2}$

For which value is the fraction not defined? i.e when is the denominator zero?

Can you make a conclusion now? - Sep 23rd 2012, 07:02 AMM670Re: Domain of a function
I believe the denominator is = to zero when x = to -4 or 4

so in interval notation I got (infinity,-4) U (4, inifinity) - Sep 23rd 2012, 07:07 AMSironRe: Domain of a function
- Sep 23rd 2012, 07:09 AMskeeterRe: Domain of a function
correction ...

$\displaystyle (-\infty,-4) \cup (-4, \infty)$

only x = -4 is not in the domain. - Sep 23rd 2012, 07:09 AMM670Re: Domain of a function
The domain is all real number excluding -4

- Sep 23rd 2012, 07:13 AMSironRe: Domain of a function
- Sep 23rd 2012, 07:16 AMM670Re: Domain of a function
Thank You to both of you

I have been stuck on this for over a day now