A ball is thrown up at the edge of a 298 foot cliff. The ball is thrown up with an initial velocity of 72 feet per second.

Its height measured in feet is given in terms of time t, measured in seconds by the equation h=-16t^2+72t+298.

a. How high will the ball go and how long does it takes to reach that height? __________ feet, ___________ seconds

b. How long does it take the ball to come back to the ground ? ___________ seconds

I have part (a) but I'm having trouble answering part (b)