r=2
center= (-1,2)
(x+1)^2 + (y-2)^2 = 2
I was thinking I just take the radius and add it + or - on the Y axis from the center?
Is there any analytical way to do this? I really don't like graphing!
Thank a lot!
r=2
center= (-1,2)
(x+1)^2 + (y-2)^2 = 2
I was thinking I just take the radius and add it + or - on the Y axis from the center?
Is there any analytical way to do this? I really don't like graphing!
Thank a lot!
I'm not sure what liking or not liking "graphing" has to do with this problem. You are told that this is a circle. Use the geometric properties of a circle.
But if you insist upon doing this "the hard way", you can write $\displaystyle (x+1)^2+ (y-2)^2= 4$ and differentiate both sides with respect to x: 2(x+1)+ 2(y-2)(dy/dx)= 0. dy/dx= -(x+1)/(y-2)= 0 at a max or min value.