Thread: How do I find the 'Highest' and 'Lowest' point of the Circle

r=2
center= (-1,2)


(x+1)^2 + (y-2)^2 = 2


I was thinking I just take the radius and add it + or - on the Y axis from the center?


Is there any analytical way to do this? I really don't like graphing!


Thank a lot!

Originally Posted by elifast

r=2
center= (-1,2)

I was thinking I just take the radius and add it + or - on the Y axis from the center?
Is there any analytical way to do this? I really don't like graphing

First note the change I made in the equation, .

The high/low points on are .

I'm not sure what liking or not liking "graphing" has to do with this problem. You are told that this is a circle. Use the geometric properties of a circle.

But if you insist upon doing this "the hard way", you can write and differentiate both sides with respect to x: 2(x+1)+ 2(y-2)(dy/dx)= 0. dy/dx= -(x+1)/(y-2)= 0 at a max or min value.