• September 16th 2012, 01:46 PM
bxuan
Thanks a bunch!
• September 16th 2012, 02:02 PM
skeeter
$f(x)$ is quadratic ...

$f(x) = ax^2 + bx + c$

$f(2x-3) = a(2x-3)^2 + b(2x-3) + c = x^2 + x - 1$

$f(2x-3) = a(4x^2-12x+9) + b(2x-3) + c = x^2 + x - 1$

$4ax^2 + (2b-12a)x + (9a-3b+c) = x^2 + x - 1$

equate coefficients ...

$4a = 1$ ... $a = \frac{1}{4}$

$2b - 3 = 1$ ... $b = 2$

$\frac{9}{4} - 6 + c = -1$ ... $c = \frac{11}{4}$

$f(x) = \frac{x^2}{4} + 2x + \frac{11}{4}$