If then
So, you will have six solutions, two for each of the 3 revolutions about the unit circle.
Can you find the remaining 4 solutions?
Hi!
I was confused with this.
I have to find all the solutions for 0<x<360^{o} if sinethreex=(square root2)/2
So I was confused with this.
I know (square root2)/2 occurs in 45^{o}, also pi/4
Then it occurs at 135^{o}, also 3pi/4
I'm not sure if these 2 are the correct solutions.
I understand where sin (the y coordinate) is (sqrt2)/2
But I'm not sure what the sinethreex means.
Can someone explain.