Hi, I'm stuck on these problems, help is appreciated. Thank you. 1. Is there an for which exists? 2. 3.
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Originally Posted by Grundsatz Hi, I'm stuck on these problems, help is appreciated. Thank you. 1. Is there an for which exists? 2. 3. For 1. the denominator is . To be able to evaluate the limit, you need to be able to cancel in the numerator. So has to be a factor. Using the factor theorem, will have as a factor if . So we have So in order for to exist, .
Originally Posted by Grundsatz 1. Is there an for which exists? Hint: so can you get rid of . How can you do that? Originally Posted by Grundsatz 2. Try factorizing , do they have a common factor? Originally Posted by Grundsatz 3. This one is easy if you get the first two.
Originally Posted by Grundsatz Hi, I'm stuck on these problems, help is appreciated. Thank you. 1. Is there an for which exists? 2. 3.
Originally Posted by Grundsatz Hi, I'm stuck on these problems, help is appreciated. Thank you. 1. Is there an for which exists? 2. 3. 3. Rationalising the numerator gives
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