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Math Help - Evaluate.

  1. #1
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    Evaluate.

    Hey guys,

    the task: Evaluate. Show necessary steps using exponent laws.

    1. (-125)^-2/3
    my answer:

    1
    ---------
    -125^2/3

    = 1
    -------------------
    cube root of 125^2

    = 1
    -----
    25

    Is that right?

    2. (2n^1/3r^-2)^0

    How can I evaluate?
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  2. #2
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    Re: Evaluate.

    Quote Originally Posted by ford2008 View Post
    Hey guys,

    the task: Evaluate. Show necessary steps using exponent laws.

    1. (-125)^-2/3
    my answer:

    1
    ---------
    -125^2/3

    = 1
    -------------------
    cube root of 125^2

    = 1
    -----
    25

    Is that right?
    Yes, it is.

    2. (2n^1/3r^-2)^0

    How can I evaluate?
    Anything to the 0 power is what?
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  3. #3
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    Re: Evaluate.

    Anyting to the power of 0 equal 1.
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  4. #4
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    Re: Evaluate.

    Can somebody explain further?
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  5. #5
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    Re: Evaluate.

    Quote Originally Posted by ford2008 View Post
    Anyting to the power of 0 equal 1.
    That is not true. 0^0 is not defined.

    Quote Originally Posted by ford2008 View Post
    Can somebody explain further?
    Now if x\ne 0 then x^0=x^{1-1}=x^1(x^{-1})=\frac{x}{x}=1~.
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  6. #6
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    Re: Evaluate.

    Explain what further? Plato gave an indication why any number (except 0) to the 0 power is 1. But you had already said that you knew that. If you are asking how that is relevant to this question, as long as neither n nor r is 0, (2n^{1/3}r^{-1/2})^0 is a non-zero number to the 0 power.
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