# Math Help - Evaluate.

1. ## Evaluate.

Hey guys,

the task: Evaluate. Show necessary steps using exponent laws.

1. (-125)^-2/3

1
---------
-125^2/3

= 1
-------------------
cube root of 125^2

= 1
-----
25

Is that right?

2. (2n^1/3r^-2)^0

How can I evaluate?

2. ## Re: Evaluate.

Originally Posted by ford2008
Hey guys,

the task: Evaluate. Show necessary steps using exponent laws.

1. (-125)^-2/3

1
---------
-125^2/3

= 1
-------------------
cube root of 125^2

= 1
-----
25

Is that right?
Yes, it is.

2. (2n^1/3r^-2)^0

How can I evaluate?
Anything to the 0 power is what?

3. ## Re: Evaluate.

Anyting to the power of 0 equal 1.

4. ## Re: Evaluate.

Can somebody explain further?

5. ## Re: Evaluate.

Originally Posted by ford2008
Anyting to the power of 0 equal 1.
That is not true. $0^0$ is not defined.

Originally Posted by ford2008
Can somebody explain further?
Now if $x\ne 0$ then $x^0=x^{1-1}=x^1(x^{-1})=\frac{x}{x}=1~.$

6. ## Re: Evaluate.

Explain what further? Plato gave an indication why any number (except 0) to the 0 power is 1. But you had already said that you knew that. If you are asking how that is relevant to this question, as long as neither n nor r is 0, $(2n^{1/3}r^{-1/2})^0$ is a non-zero number to the 0 power.