Thread: Express each power as a radical.

Hi guys,

the task: Express each power as a radical.

1. 9^1/2
my anser:

= root of 9

2. m^-1/2
my answer:

= 1
------
m^1/2

= 1
--------
root of m

3. 3k^2/5
my answer:

= 5 root of 3k^2

4. ((pq^3)^4)^1/5
my answer:

= 5 root of pq^12

5. x^2/3 y^1/4
-------------
x^1/2 y^1/2

my answer:

= x^4/6-3/6 y^1/4-2/4

= x^1/6 y^-1/4

Is that right? If not, please explain. Thanks.

Originally Posted by ford2008

Hi guys,

the task: Express each power as a radical.

1. 9^1/2
my anser:

= root of 9

2. m^-1/2
my answer:

= 1
------
m^1/2

= 1
--------
root of m

3. 3k^2/5
my answer:

= 5 root of 3k^2

4. ((pq^3)^4)^1/5
my answer:

= 5 root of pq^12

5. x^2/3 y^1/4
-------------
x^1/2 y^1/2

my answer:

= x^4/6-3/6 y^1/4-2/4

= x^1/6 y^-1/4

Is that right? If not, please explain. Thanks.

Your notation on 3 and 4 are possibly wrong.

3. Is this or If it is the second one then you are correct.

4. Is this or

The other ones look good.

-Dan

Hey Dan,

thanks for your help.

No. 3. is the first one, so then I am wrong. But what is wrong then in my answer?

No. 4. is the first one. So is my answer right or not, if it is the first one?

Thanks for your help.

Originally Posted by ford2008

3. 3k^2/5
my answer:

= 5 root of 3k^2

4. ((pq^3)^4)^1/5
my answer:

= 5 root of pq^12

#3 NOT

$4

Originally Posted by ford2008

Hi guys,

the task: Express each power as a radical.

...
3. 3k^2/5
my answer:

= 5 root of 3k^2

4. ((pq^3)^4)^1/5
my answer:

= 5 root of pq^12

...

Originally Posted by ford2008

...

No. 3. is the first one, so then I am wrong. But what is wrong then in my answer?

No. 4. is the first one. So is my answer right or not, if it is the first one?

Thanks for your help.

According to your answer the 3 in your term doen't belong under the root-sign: