1. ## Rationalize the Denominator

I can't seem to solve this one. I tried reversing the signs, which didn't work for me. How do I solve this one?

2. ## Re: Rationalize the Denominator

Originally Posted by Diesal
Multiply numerator and denominator by $\displaystyle (1-\sqrt{3}+\sqrt{5})$

3. ## Re: Rationalize the Denominator

that won't quite do the job.

$\displaystyle (1 + \sqrt{3} - \sqrt{5})(1 - \sqrt{3} + \sqrt{5}) = 1^2 - (\sqrt{3} - \sqrt{5})^2$

$\displaystyle = 1 - (3 - 2\sqrt{15} + 5) = -7 + 2\sqrt{15}$, which certainly isn't rational.

i propose instead multiplying top and bottom by:

$\displaystyle 7 + 3\sqrt{3} + \sqrt{5} + 2\sqrt{15}$, since:

$\displaystyle (1 + \sqrt{3} - \sqrt{5})(7 + 3\sqrt{3} + \sqrt{5} + 2\sqrt{15}) = 11$

4. ## Re: Rationalize the Denominator

You are correct. I entered is incorrectly into my CAS.

5. ## Re: Rationalize the Denominator

Originally Posted by Deveno
that won't quite do the job.

$\displaystyle (1 + \sqrt{3} - \sqrt{5})(1 - \sqrt{3} + \sqrt{5}) = 1^2 - (\sqrt{3} - \sqrt{5})^2$

$\displaystyle = 1 - (3 - 2\sqrt{15} + 5) = -7 + 2\sqrt{15}$, which certainly isn't rational.
Though you could then multiply top and bottom by \displaystyle \displaystyle \begin{align*} -7 - 2\sqrt{15} \end{align*}...