Thread: Find the requested function value meeting all of the given conditions??

I have to do this packet for an AP class I'm taking, and my teacher didn't give me anything to work with. I'm desperate.

sin(theta)= (square root)3/2 and tan(theta) > 0 ; Find cos(theta).

Darw a circle with radius=1 and center at (0,0) then on sin axis go up as much as squrt(3)/2, draw a horizontal line to intersect circle at two points...now draw tan axis and check which of the two points on circle qualifies for tan>0

Hello, MaddyV!

is positive: . is in Quadrant 1 or Quadrant 2.

is positive: . is in Quardrant 1 or Quadrant 3.

. . Hence, is in Quadrant 1.




is in a right triangle with: .
Pythagorus tell us that: .

Therefore: .

Okay, so how about:

cos(theta) = - [(square root)2]/2 and tan(theta) < 0 ; find cot(theta) ?

Originally Posted by MaddyV

Okay, so how about:

cos(theta) = - [(square root)2]/2 and tan(theta) < 0 ; find cot(theta) ?

did you not learn this in your pre-AP class?

you are expected to already know the values for sine and cosine on the unit circle and the definitions/identities for basic all six trig ratios ...

It was actually recommended that I skip Pre-Calculus and go straight to AP Calculus AB. I was given a summer packet with these problems specifically so I could learn how to do these things.

Why was this recommended? The only way I would recommend something like this is if you have shown that you already know how to do the topics in Pre-Calculus...

Originally Posted by MaddyV

It was actually recommended that I skip Pre-Calculus and go straight to AP Calculus AB. I was given a summer packet with these problems specifically so I could learn how to do these things.

Whoever "recommended" this idea has set you up for failure. My advice is for you to get into a precalculus class ... now.

Truth is, you're not ready for AP calculus.