I am given a base function of f=x2
and given a transformed equation of y = 7f((-1/6)(x-1))+1
I am being asked to describe the transformations that must be applied to the graph of the base function f(x) to obtain the transformed function, which I understand, and then I am ask to write the transformed equation in simplified form. This is where I'm hung up.
I guess the next line would be
y=7((-1/6)(x-1)2+1This is where I get stuck. How do I multiply -1/6 by x-1? What do I do with the square? Also, I don't know how to write fractions on the site yet, so -1/6 is negative one sixt to clear up any confusion. I've placed it in parenthesis to try to indicate that.