Hi, I need help with the following question in the attachment. It is about logs, I don't understand this problem. Please help, thanks in advanced :)

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- Aug 6th 2012, 10:01 PMdan713Logarithmic expressions
Hi, I need help with the following question in the attachment. It is about logs, I don't understand this problem. Please help, thanks in advanced :)

- Aug 6th 2012, 10:13 PMrichard1234Re: Logarithmic expressions
Note that $\displaystyle \log_8 {64} = 2$. Also, $\displaystyle \log_8 {64} = 3 \log_8 {4}$ by a logarithmic identity. Therefore

$\displaystyle 3 \log_8 {4} = 2 \Rightarrow \log_8 {4} = \frac{2}{3}$. - Aug 7th 2012, 08:03 AMdan713Re: Logarithmic expressions
There is no exponent 3 though. How did you end up with log64 base 8?

- Aug 7th 2012, 08:16 AMrichard1234Re: Logarithmic expressions
I'm using 64 because $\displaystyle 64 = 4^3 = 8^2$.

- Aug 7th 2012, 08:43 AMPlatoRe: Logarithmic expressions
- Aug 7th 2012, 08:51 AMrichard1234Re: Logarithmic expressions