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Math Help - Solve 4x-y+2z=1

  1. #1
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    Solve 4x-y+2z=1

    How do we solve 4x-y+2z=1? What does it even mean to "solve" this? (I can solve 4x=1). Thanks.
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  2. #2
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    Re: Solve 4x-y+2z=1

    You can't solve for a unique solution. All solutions (x,y,z) lie on a plane.
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  3. #3
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    Re: Solve 4x-y+2z=1

    Oh, hehe. I misunderstood the question on an honors precalculus study guide. I thought the question was:
    Solve $4x-y+2z=1$
    Solve $x+3y-z=2$, and
    Solve $7x+4y+5z=3$.

    The question is actually:
    Solve the system
    $4x-y+2z=1$
    $x+3y-z=2$
    $7x+4y+5z=3$.

    Which is easy. Stupid mistake.
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