# Solve 4x-y+2z=1

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• August 1st 2012, 06:40 PM
mathDad
Solve 4x-y+2z=1
How do we solve $4x-y+2z=1$? What does it even mean to "solve" this? (I can solve 4x=1). Thanks.
• August 1st 2012, 09:18 PM
richard1234
Re: Solve 4x-y+2z=1
You can't solve for a unique solution. All solutions (x,y,z) lie on a plane.
• August 2nd 2012, 07:39 AM
mathDad
Re: Solve 4x-y+2z=1
Oh, hehe. I misunderstood the question on an honors precalculus study guide. I thought the question was:
Solve \$4x-y+2z=1\$
Solve \$x+3y-z=2\$, and
Solve \$7x+4y+5z=3\$.

The question is actually:
Solve the system
\$4x-y+2z=1\$
\$x+3y-z=2\$
\$7x+4y+5z=3\$.

Which is easy. Stupid mistake. :D