# Thread: Help with Partial Fraction Decompostion

1. ## Help with Partial Fraction Decompostion

I know what the answer is but just can't seem to do the actual decomposition.

Can anyone help?

4x - 4 / (x2-4x+4)

2. ## Re: Help with Partial Fraction Decompostion

Can you factorise the denominator?

3. ## Re: Help with Partial Fraction Decompostion

$\displaystyle \frac{4x-4}{x^2-4x+4} = \frac{4(x-1)}{(x-2)^2} = \frac{A}{x-2} + \frac{B}{(x-2)^2}$

$\displaystyle 4(x-1) = A(x-2) + B$

let $\displaystyle x = 2$ ...

$\displaystyle B = 4$

let $\displaystyle x = 1$

$\displaystyle 0 = -A + 4$

$\displaystyle A = 4$

$\displaystyle \frac{4x-4}{x^2-4x+4} = \frac{4}{x-2} + \frac{4}{(x-2)^2}$

4. ## Re: Help with Partial Fraction Decompostion

Thank you very much!!

You have helped a great deal - now I can finish my assignment.