# Help with Partial Fraction Decompostion

• Jul 20th 2012, 07:08 AM
tammmyl
Help with Partial Fraction Decompostion
I know what the answer is but just can't seem to do the actual decomposition.

Can anyone help?

4x - 4 / (x2-4x+4)

• Jul 20th 2012, 07:26 AM
a tutor
Re: Help with Partial Fraction Decompostion
Can you factorise the denominator?
• Jul 20th 2012, 07:28 AM
skeeter
Re: Help with Partial Fraction Decompostion
$\frac{4x-4}{x^2-4x+4} = \frac{4(x-1)}{(x-2)^2} = \frac{A}{x-2} + \frac{B}{(x-2)^2}$

$4(x-1) = A(x-2) + B$

let $x = 2$ ...

$B = 4$

let $x = 1$

$0 = -A + 4$

$A = 4$

$\frac{4x-4}{x^2-4x+4} = \frac{4}{x-2} + \frac{4}{(x-2)^2}$
• Jul 20th 2012, 08:13 AM
tammmyl
Re: Help with Partial Fraction Decompostion
Thank you very much!!

You have helped a great deal - now I can finish my assignment.