a) (sqrt3 - i)^6 b) (2-2i)^5
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Originally Posted by kalemale a) (sqrt3 - i)^6 b) (2-2i)^5 and
Last edited by Plato; July 17th 2012 at 04:25 AM.
Originally Posted by Plato OP, even experts make tiny mistakes sometimes. I hope i got that right.
sorry if I dont understand fully but why is it -pi/4 and -pi/6
Originally Posted by kalemale sorry if I dont understand fully but why is it -pi/4 and -pi/6 If you plot the complex number on the complex plain and convert to polar coordinates you get and . Stated another way: . Now to raise it to the 6th power apply de Moivre's theorem:
so we get -pi / 6 becouse its negativ and the angle is 30 degress?
Originally Posted by kalemale so we get -pi / 6 becouse its negativ and the angle is 30 degress? Yes - the angle is negative 30 degrees.
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