I can't find anything online to help me with this one, hopefully someone can help. The base of a triangle is 5m less than twice the height. If the area is 90m(squared) how long is the base and height?
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Let h be the height. Then the base is 2h-5. Area = (1/2)base*height, so $\displaystyle \frac{1}{2}h(2h-5) = 90$ Solve for h.
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