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Math Help - How to find the intercepts of y=x^3-3x

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    How to find the intercepts of y=x^3-3x

    How to find the intercepts of y=x^3-3x. I keep coming up with x intercept= (sq.rt. 1, 0) and y intercept (0,0) but was told a part of that answer or the whole thing is wrong or it is incomplete.
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    Re: How to find the intercepts of y=x^3-3x

    Quote Originally Posted by kmerr98277 View Post
    How to find the intercepts of y=x^3-3x. I keep coming up with x intercept= (sq.rt. 1, 0) and y intercept (0,0) but was told a part of that answer or the whole thing is wrong or it is incomplete.
    There are three x-intercepts. Solve x(x^2-3)=0~.
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    Re: How to find the intercepts of y=x^3-3x

    (x^2-3) factors to (x-3) and (x-1). so...x intercepts are (3,0) and (-1,0)?
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    Re: How to find the intercepts of y=x^3-3x

    Quote Originally Posted by kmerr98277 View Post
    (x^2-3) factors to (x-3) and (x-1).
    No it does not factor that way.

    (x^2-3)=(x-\sqrt3)(x+\sqrt3)
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    Re: How to find the intercepts of y=x^3-3x

    so... x intercepts are (sq.rt.3,0) and (-sq.rt.3, 0) and i have no idea about the third intercept. How do you enter symbols into the forum? Thanks a lot!!
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    Re: How to find the intercepts of y=x^3-3x

    Quote Originally Posted by kmerr98277 View Post
    i have no idea about the third intercept. How do you enter symbols into the forum?
    The third is (0,0)

    [TEX](x-\sqrt{3})(x+\sqrt{3})[/TEX] gives (x-\sqrt{3})(x+\sqrt{3})
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