How to find the intercepts of y=x^3-3x. I keep coming up with x intercept= (sq.rt. 1, 0) and y intercept (0,0) but was told a part of that answer or the whole thing is wrong or it is incomplete.
How to find the intercepts of y=x^3-3x. I keep coming up with x intercept= (sq.rt. 1, 0) and y intercept (0,0) but was told a part of that answer or the whole thing is wrong or it is incomplete.
There are three x-intercepts. Solve $\displaystyle x(x^2-3)=0~.$
so... x intercepts are (sq.rt.3,0) and (-sq.rt.3, 0) and i have no idea about the third intercept. How do you enter symbols into the forum? Thanks a lot!!